Coordination geometry: why is of Cu (acac)2 square planar?
2017年1月29日 · To get to a $\ce{[Cu(acac)3]}$ complex, you would have to either 1) adopt a perfect octahedral environment and sacrifice the electronic stabilisation from the Jahn-Teller distortion; or 2) stretch two of the acac ligands to a longer length than they would like to be.
Why is tetraamminecopper (II) a square planar and not a …
2015年7月23日 · The charge of bivalent cation $\ce{Cu^{2+}}$ is large enough to bond four charged ligands if available, such as in $\ce{[CuCl4]^{2-}}$, but the ligands are bound weakly and easily dissociate. However, $\ce{Cu^{+2}}$ ions usually adopt a distorted octahedral geometry, with two ligands having a longer bond length than the four others.
Why are square planar coordination compounds with four …
2017年4月23日 · Why do square planar coordination compounds of type $\\ce{[Mabcd]}$ not show optical activity, although they contain 4 different ligands (i.e. chiral central metal atom)?
bond - Geometry of Ni (acac)2 - Chemistry Stack Exchange
2020年1月20日 · The complex $\ce{Ni(acac)2}$ is paramagnetic as expected , i.e it has two unpaired electrons giving rise to a magnetic moment of $ \sqrt{8}$ BM but doesn't have the tetrahedral geometry consistent with the CFT assumptions , why ? well if the above thing is true then what is the actual structure of the complex ? please help !
Tetrahedral or Square Planar - Chemistry Stack Exchange
2013年4月12日 · $\ce{Ni^{+2}}$ produces a square planar complex with $\ce{CN-}$, as cyanide is a strong ligand. Nickel carbonyl, on the other hand, exists as a tetrahedral complex because nickel's oxidation is 0. You shall be able to use this method most of the time, but in certain cases, there are some exceptions.
Coordination compound nomenclature for [Cu (acac) (bpy)]BPh4
2020年10月14日 · Coordination compound nomenclature for [Cu(acac)(bpy)]BPh4. Ask Question Asked 4 years, 1 month ago.
Why is the tetraamminecopper (II) ion square planar?
2017年7月1日 · Coordination geometry: why is of Cu(acac)2 square planar? 6 Why does steric hindrance cause a d8 complex to have a tetrahedral geometry rather than a square planar geometry?
inorganic chemistry - Why is the crystal field splitting energy larger ...
2020年5月16日 · I think in octahedral field placement of ligands both $\mathrm d_{x^2-y^2}$ and $\mathrm d_{z^2}$ orbitals of the metals face direct contact with the ligand (when compared to only $\mathrm d_{x^2-y^2}$ orbital in the corresponding square planar complex) and hence they must experience more repulsion. As the result, there must be greater ...
C4v point group complexes and the group orbitals (MO Theory)
2019年2月14日 · For b1, I get something of the form 5+3-4-2 (ie opposite corners are same phase) and for e I get 2-4 or 3-5 (only two ligands- opposite corners out of phase). The e orbitals match up to the metal px and py, the b1 to d(x2-y2) and the a1's to …
Why can copper have multiple coordination numbers? [closed]
Note that in aquaeous solution the ligand sphere of the seemingly so stable complex $\ce{[Cu(H2O)6]^2+}$ is in constant fluctuation with dissociating and reassociating ligands. Otherwise, there would be no rapid exchange mechanism that would allow the formation of $\ce{[Cu(NH3)4(H2O)2]^2+}$ upon addition of concentrated ammonia.