What: One of the natural wonders of Brazil. Admittedly, Brazil is not a country lacking in things both natural and wonderful, but the Meeting Of The Waters is one of the most unmissable.
We’re excited to announce that Sir Rod Stewart will play the Sunday teatime legend slot at Glastonbury 2025, with his first performance at Worthy Farm since headlining the Pyramid Stage in 2002. Said ...
Rock legend Sir Rod Stewart rock legend said that he had expected to live in the Jacobean-style property for the rest of his life when he put it on the market for £7.5 million in 2016 to move clo ...
SIR Rod Stewart has been announced for Glastonbury Festival's Legends slot next summer. The 79-year-old confirmed the news on social media today, writing: "I’m absolutely thrilled to announce ...
I'll see you there!" Sir Rod will be 80 when the festival takes place between 25 and 29 June next year at Worthy Farm in Somerset. Festival co-organiser Emily Eavis shared the same image of Sir ...
Sir Rod Stewart greeted the announcement that he will play the coveted Sunday Legend’s Slot at next year’s Glastonbury by promising “to pleasure and titillate” the Pyramid Stage crowd.
Rod Stewart found everlasting love with Penny Lancaster - but their marriage has been far from plain sailing. The rock legend, 79, has been announced as the first star to play next year's ...
Sir Rod Stewart is making an iconic return to live performance as he's announced as the first star to play next year's Glastonbury Festival. The 79-year-old legend announced the incredible news on ...
Glastonbury Festival have confirmed that Rod Stewart will be headlining their Sunday teatime legend slot for next year. The news comes just days after the 79 year old announced his intention to ...
One wrote on X, formerly Twitter: “Rod Stewart needs to retire. The legends slot will be painful to watch/listen to #Glastonbury.” “Rod Stewart headlining Glastonbury legends stage.
[oÛ^0Ž­ ¶^ ¯ ¡wµôöp~ €•“V €ªEBæ «?~ýùç¿??ppýÿÿÿ C#c S3s K+k [;{ G'g W7w O/o _? Ï›?ëÿ žÉHh× © ¿|L v*!)ºI% HUw 6GØ2(1’[’!4ø ...