The deceleration = velocity change/time = (0 m/s – 12 m/s) ÷ 10 s = -1.2 m/s 2 The distance travelled while decelerating = area of triangle = ½ × 10 s × 12 m/s = 60 m The total distance ...

Key fact The gradient of speed-time and velocity-time graphs represent acceleration. The area under a speed-time graph represents the distance travelled. The object is accelerating at \(\frac{8}{ ...