Therefore since the trig equation we are solving is sin and it is positive (0.5 ... we need to use the rule in the 2nd quadrant. From the graph of the function, we can see that we should be ...
An object is moving counter-clockwise along a circle with the centre at the origin. At \(t=0\) the object is at point \(A(0,5)\) and at \(t=2\pi\) it is back to point \(A\) for the first time.
An object is moving counter-clockwise along a circle with the centre at the origin. At \(t=0\) the object is at point \(A(0,5)\) and at \(t=2\pi\) it is back to point \(A\) for the first time.