Therefore since the trig equation we are solving is sin and it is positive (0.5 ... we need to use the rule in the 2nd quadrant. From the graph of the function, we can see that we should be ...

Solve the equation \(4\sin x^\circ - 3 = 0\), where \(0 \le x \textless 360\). From the graph of the function, we can see that we should be expecting 2 solutions: 1 solution between \(0^\circ ...